Description Olivier Thomann 2004-12-10 17:27:47 EST

Using latest, that code compiles fine, but it should fail because two methods
are inherited with the same signature.

class A<T> {
    void foo(T t) {}
    void foo(String i) {}
}

public class X<T> extends A<String> {}

If you change it for:
class A<T> {
    void foo(T t) {}
    void foo(String i) {}
}

public class X<T> extends A<String> {
	public static void main(String[] args) {
		new X<String>().foo("");
	}
}

We do report an ambiguous call.
----------
1. ERROR in C:\tests_sources\X.java (at line 8)
	new X<String>().foo("");
	                ^^^
The method foo(String) is ambiguous for the type X<String>
----------
1 problem (1 error)