Description Andrew Clement 2012-02-15 17:16:16 EST

If you have a type with multiple type params, like this:

Foo<?,T>

the signature is:

LFoo<*TT;>;

and the handling of * is not working in TypeFactory.  If that signature is passed in it will actually build:

Foo<?>

having lost the second type parameter, this breaks code later that has expectations on the number of params.  (e.g. ArrayIndexOutOfBoundsException when building parameterization map)