Description Erik Johnson 2003-02-11 16:13:33 EST

The following legal code results in compile error, which shouldn't be the case:

package beans;
public abstract class Base {
	abstract void doSomething();
}

package beans;
public abstract class SubClass extends Base {
	public final void doSomething() {
		System.out.println("hello world");
	}
	public void anotherMethod() {
	}
}

package beans.test;
import beans.SubClass;
public class TestClass extends SubClass {
	public void anotherMethod() {
		super.anotherMethod();
	}
}

In this case, the base class in package "beans" defines a package-private 
method doSomething() which the subclass, "SubClass" implements as a public 
final method.  Any class that extends from "SubClass" but is in a different 
package, then contains the following compile error:
"This class must implement the inherited abstract method Base.doSomething(), 
but cannot override it since it is not visible from TestClass. Either make the 
type abstract or make the inherited method visible."

Making the Base.doSomething() public will fix this error; however this isn't a 
Java error--this compiles fine using javac and older Eclipse versions.

Environment:
JDK 1.4.1_01
Eclipse M5