[news.eclipse.tools.jdt] Re: Getting superclass/superinterfaces from an

[exquisitus <no.spam@xxxxxxxxxxxxxxx>]

Daniel Megert schrieb:
> exquisitus wrote:
> > Hi,
> >
> > Sorry if the question has been already answered, but I didn't found 
> > the (entry) point... :-(
> >
> > How may I determine the superclass(es) from a given source IType. I'm 
> > finally interested in deciding, if a IMethod overrides a derived one 
> > and/or implements an interface method.
> For a pointer take a look at the methods in 
> org.eclipse.jdt.internal.corext.util.JavaModelUtil.
>
> Dani
> > Thanks in advance,
> > Sven

Got it. Just for Thread completion:

IMethod method = ...
IType type = method.getDeclaringType();
ITypeHierarchy typeHierarchy = type.newSupertypeHierarchy(null);
IType superclass = typeHierarchy.getSuperclass(type);
while(superclass != null) {
	IMethod[] methods = superclass.getMethods();
                  for (IMethod superMethod : methods) {
                     if (equals(method, superMethod)) {
                        // is derived method
                     }
                  }
}

   static boolean equals(IMethod m1, IMethod m2) throws 
JavaModelException {
      if (m1 == m2) return true;
      if (m1 == null || m2 == null) return false;

      boolean b = m1.getElementName().equals(m2.getElementName());

      String r1 = m1.getReturnType();
      String r2 = m2.getReturnType();

      b = b && equals(r1, r2); // null safe equals

      String[] p1 = m1.getParameterTypes();
      String[] p2 = m2.getParameterTypes();

      b = b && Arrays.deepEquals(p1, p2);

      String[] e1 = m1.getExceptionTypes();
      String[] e2 = m2.getExceptionTypes();

      b = b && Arrays.deepEquals(e1, e2);

      return b;
   }

   static boolean equals(String s1, String s2) {
      if (s1 == s2) return true;
      if (s1 == null || s2 == null) return false;
      return s1.equals(s2);
   }