[News.eclipse.technology.mylar] Re: How to get information on one single

[Remy Suen <remy.suen@xxxxxxxxx>]

Thank you Robert, that link did it.

For anyone that's hitting this from Google, the basic code is as follows:

BugzillaRepositoryConnector connector = new BugzillaRepositoryConnector();
connector.init(new TaskList());
TaskRepository repository = new TaskRepository(
        BugzillaCorePlugin.REPOSITORY_KIND,
        "https://bugs.eclipse.org/bugs/";);

try {
    AbstractRepositoryTask task = connector.createTaskFromExistingKey(
            repository, "150000"); // bug number
} catch (CoreException e) {
    e.printStackTrace();
}

Regards,
Rem

On Mon, 02 Apr 2007 11:01:51 -0700, Robert Elves wrote:

> Remy, have a look at:
> 
> http://wiki.eclipse.org/index.php/Mylar_Integrator_Reference#Bugzilla_API_.28org.eclipse.mylar.bugzilla.core.29_HEADLESS
> 
> -Rob
> 
> Remy Suen wrote:
>> Hi,
>> 
>> I've hacked around with the Mylar code and was able to figure out how to
>> query bugzilla as if I was using the query.cgi page but have been unable
>> to get anywhere in terms of getting information about one single bug.
>> 
>> I know I can iterate over my query's QueryHitCollector and get each
>> individual AbstractQueryHit and call public get methods from it, but
>> what I want is the functionality to just pass in a bug # and be able to
>> get a returned AbstractRepositoryTask.
>> 
>> What is the shortest (and crudest?) method possible to achieve this with
>> the minimal lines of code? As you can tell, I am already using the
>> internal Bugzilla classes, so I wouldn't mind making other internal API
>> calls if necessary.
>> 
>> Thank you,
>> Regards,
>> Remy