[news.eclipse.platform] Re: File Path API

[Tom Schindl <tom.schindl@xxxxxxxxxxxxxxx>]

Hi,

why don't you simple call
----------8<----------
InputStream in = 
Platform.getBundle("com.my.plugin").getResource("my.file").open();
----------8<----------

Tom

Praveen schrieb:
> Hi John,
>
> Thank you for your reply. I am trying to use the API as you suggested, but am not able to get a path. In fact the getProject returns me a project even when the project does not exist. 
>
> I just realized that I should not be accessing the resource as a file path, because if the plugin is deployed as a jar, then the jar would need to be extracted to a temp location for the absolute path to be valid.
>
> Is there a better way to access a resource contained in a plugin folder?
>
> Regards Praveen.
>   "John J. Barton" <johnjbarton@xxxxxxxxxxxxxxx> wrote in message news:ekth5d$skj$1@xxxxxxxxxxxxxxxxxxxx
>   Maybe this will give you some hints as to which API to look into:
>
>   IProject project = 
>   ResourcesPlugin.getWorkspace().getRoot().getProject(best_project_match);
>
>   IPath as_specific_as_possible = source_path;
>   if (project.exists()) {
>     iseg++; // skip project name
>     IPath resourcePath = source_path.removeFirstSegments(iseg);
>     IResource resource = project.findMember(resourcePath);
>     as_specific_as_possible = resource.getLocation();
>     if (as_specific_as_possible == null) {
>   as_specific_as_possible = path; // someone lied
>     }
>   } // else not in workspace
>
>   If you really want a URL, then try something like
>      path.toFile().toURI().toURL();
>
>   Praveen wrote:
>   > Hi,
>   >  
>   > I am writing a plugin and need to access a file within one of the folder.
>   >  
>   > I tried using URL u=this.getClass().getResource("/Profile/Profile.uml2");
>   >  
>   > But this returns a path of the eclipse installation. Is there any other 
>   > API which can return the path of the file?
>   >  
>   > Thanks Praveen.