[news.eclipse.newcomer] Setting initial position of a PopupDialog

[aniket.patil@xxxxxxxxx (Aniket S. Patil)]

I have a table displayed in one of my views. When i click on a particular 
row in my table, a PopupDialog is displayed which shows a list of 
operations available for the table row (Edit and Delete the row).

I need the PopupDialog to be displayed next to where i have clicked. Since 
the default inital position for a Dialog is taken from the Window class 
(which displays it in the centre of the screen), i am overriding the 

protected Point getInitialLocation(Point initialSize) {}

method, by returning a new Point(x,y). To get the x and y co-ordinates, i 
have a selectionListener for the table. From the SelectionEvent object of

public void widgetSelected(SelectionEvent e), 

i get e.x and e.y and set them to x and y of the above point.

According the API description, e.x and e.y give the co-ordinates of the 
selected area. However, their value always turns out to be 0. The Point 
returned from getInitialLocation is (0,0) and hence the PopupDialog is 
always in the left hand corner of the screen.

How do i get the current x and y postion (of the point i click on the 
table), so that i can position the dialog close to my click?