[news.eclipse.modeling.tmf] Re: [XText] serialize parsed tree to String

[Sebastian Zarnekow <Sebastian.Zarnekow@xxxxxxxxx>]

Hi Michael,

your resource is emtpy and has not been loaded.

Please try something like:

Resource res = resourceSet.getResource(URI.createURI(..existing uri..));
res.save(..);

resourceSet.createResource will create a new resource but won't load it.

res = resourceSet.createResource(..uri..);
res.load(new StringInputStream("valid model"));
res.save(..)

should do the trick as well.

Hope that helps,
Sebastian
--
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Michael Burkhardt schrieb:
> Hi Sebastian,
>
> nice to read you again.
>  > Where did you get your model from?
> I use your cool Inject-stuff.
>
>  > Did you parse it and try to serialize it back [...]
> I try to serialze my parsed model into text again.
>
> May the documentation I searched for is that 
> [http://www.eclipse.org/Xtext/documentation/latest/xtext.html#serialization]. 
>
>
>
> When I try to serialize my parsed DSL model, currently I got a 
> NullPointerException in XtextResource line 184.
> line 184: if (contents.size() != 1)
>
> It seems that 'contents' was not set.
>
>
> How do I reached this?
>
> line 1: Injector injector = new 
> DslStandaloneSetup().createInjectorAndDoEMFRegistration();
> line 2: xtextResource = injector.getInstance(XtextResource.class);
> line 3: ByteArrayOutputStream bos = new ByteArrayOutputStream();
> line 4: xtextResource.save(bos, new HashMap());
>
>
> My second try with the same result was:
> line 1: Injector injector = new 
> DslStandaloneSetup().createInjectorAndDoEMFRegistration();
> line 2: xtextResourceSet = injector.getInstance(XtextResourceSet.class);
> line 3: xtextResourceSet.addLoadOption(XtextResource.OPTION_RESOLVE_ALL, 
> Boolean.TRUE);
> line 4: xtextResource = (XtextResource) 
> xtextResourceSet.createResource(org.eclipse.emf.common.util.URI.createURI("dummy:/dummy.jadl")); 
>
> line 5: ByteArrayOutputStream bos = new ByteArrayOutputStream();
> line 6: xtextResource.save(bos, new HashMap());
>
>
>
> Ciao, Micha
>
>
>
>
>
>
>
>
> --- Original-Nachricht ---
> Absender: Sebastian Zarnekow
> Datum: 11.09.2009 17:28
> > Hi Micha,
> >
> > resource.save(OutputStream, Map) should do the job - if your model is 
> > contained this resource (resource.getContents().add() will add it to 
> > your resource if necessary). Usually there is no need to obtain a 
> > SerializerUtil.
> > However there seem to be some inconsistencies in your model that lead 
> > to the situation where it cannot be serialized to a valid concrete 
> > syntax. Where did you get your model from? Did you parse it and try to 
> > serialize it back or did you create it from an m2m transformation or 
> > something similar?
> >
> > Maybe you can provide a small reproducable example and file a bug?
> >
> > Regards,
> > Sebastian