[news.eclipse.modeling.m2m] Re: [QVT] its output model is in only XMI?

["Radek Dvorak" <radek.dvorak@xxxxxxxxxxx>]

Hi David,

You are right, the output will not be XMI and EMF involves exactly the  
mechanism I have decribed.
There is XSDResourceImpl with custom serialization and is applied to *.xsd.

The following code snippet loads a schema file into QVT transf as a XSD  
model.
--
 modeltype XSD uses "http://www.eclipse.org/xsd/2002/XSD";;

 transformation FooXSD(inout inOutModel : XSD);

 main() {
      var schemas : Collection(XSDSchema)  :=  
inOutModel.rootObjects()[XSDSchema];
 }
--
As for validation, in case you can deserialize xsd file as a XSD model,
it conforms to XSD.ecore metamodel.
But I'm not sure this way is what you are looking for ;-).

You can also build a XSD model instance as the output of the transf and  
save it as
myOut.xsd.

I have just explained a bit what you can do with QVTO in this case,
so about XSD Schema and XMI specific questions I suggest you to ask in EMF  
newsgroup.

Regards,
/Radek



On Mon, 02 Jun 2008 21:10:00 +0200, David <David-392.Li@xxxxxxxxxxxxxxxxx>  
wrote:

> Thanks Radek. Can I have further clarification?
>
> Assume that I just want to use default serialization format (no  
> customized implementation as you suggested).
>
> If I want to transform a model A which conforms to a  
> intermediateModel.ecore into a XSD model which conform to XSD.ecore  
> model (org.eclipse.xsd), in this case, what is the serialization format  
> for the outout XSD model? Because xsd package does not use XMI  
> serialization format, can I understand that I will get a xsd schema, not  
> XMI formated output file? If I get a xsd schema file, how can I validate  
> that it conforms to the XSD.ecore model? Too many questions, because I  
> am new to EMF and m2m/QVT.
>
> Thanks again.



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