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Re: [tcf-dev] IProcesses.start() not working
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In the case when we run remote process invoke from client, what would be privileges available for that call.
Because I notice I am not providing any user id and password while I make a call to the target machine.
- Prasad
-----Original Message-----
From: tcf-dev-bounces@xxxxxxxxxxx [mailto:tcf-dev-bounces@xxxxxxxxxxx] On Behalf Of Frederic LEGER
Sent: Tuesday, June 20, 2017 1:31 AM
To: tcf-dev@xxxxxxxxxxx
Subject: Re: [tcf-dev] IProcesses.start() not working
Prasad,
I am not sure about the java part, but at least with python, you have to register (subscribe) a StreamListener for the "ProcessesV1" type.
You may have a look at the python sources : tcf/tests/ProcessStart.py
Hope this helps
DERF
On 06/15/2017 10:46 PM, Nair, Prasad wrote:
> Hello,
>
> I am trying to invoke a remote process on the target device from my
> host machine. The message says the process was started without any
> errors , but my remote process is supposed to generate an output file.
> That's not getting generated.
>
> String arg_array[] = { "-l" ,">", "LSOUTPUT.txt"
> };
>
> serv.start("/myname/lsexample", "ls", arg_array,
> *null*, *false*, *new* IProcesses.DoneStart() {
>
> IStreams streamsService;
>
> @Override
>
> *public* *void* doneStart(IToken token, Exception error,
> ProcessContext
> process) {
>
> *if* (error == *null*) {
>
>
> System.out.println("Newly started process: " + process.getName() + " "
> + process.getID());
>
>
> System.out.println("IProcesses service: [start] test ok.\n");
>
> } *else*
>
>
> System.out.println("ls invoke fail ! Error from agent:" +
> error.getMessage());
>
> }
>
> });
>
> But I don't see a LSOUTPUT.txt file generated. I get this in the
> output
>
> Newly started process: -l P1089
>
> IProcesses service: [start] test ok.
>
> Why is it saying -l as for process.getName() it should be "ls" instead.
> Any idea why that's happening ?
>
> Thanks,
>
> Prasad
>
>
>
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