Re: [paho-dev] Resource temporarily unavailable

[Roger Light <roger@xxxxxxxxxx>]

Hi Jon,

This was a problem with some new code that only manifested itself with
relatively large publish messages. Thanks for reporting it. I've
committed a fix and pushed an updated version to pypi.

On a general note, you should only use one of loop_start(),
loop_forever() and loop().

Cheers,

Roger


On Sun, Mar 16, 2014 at 6:14 PM, Jon Mansey <jon@xxxxxxxxxx> wrote:
> Hi, new to the list, new to mqtt, loving it so far.
>
> I have small message feeds working great, both publish and subscribe, now Im trying to publish a ~90KB file and am getting what looks like a socket error on loop, see below.
>
> from searching the issue I found a loop_forever is needed when sending binaries/files, when i added the loop_forever, the resource unavailable error started. without the loop_forever, the file just wouldn’t send, the client would exit immediately with nothing sent.
>
> Any input or feedback much appreciated.
>
> client OS is angstrom linux
>
> ~# python pushcap.py
> Traceback (most recent call last):
>   File "pushcap.py", line 20, in <module>
>     rc = mqttc.loop(2)
>   File "/usr/lib/python2.7/site-packages/paho/mqtt/client.py", line 790, in loop
>     self._sockpairR.recv(1)
> socket.error: [Errno 11] Resource temporarily unavailable
>
> here’s my client code
>
> :~# cat pushcap.py
> import paho.mqtt.client as mqtt
>
> def on_publish(foo, userdata, bar):
>   # Disconnect after our message has been sent.
>     print "published"
>     mqttc.disconnect()
>
> mqttc = mqtt.Client()
> mqttc.on_publish = on_publish
> mqttc.connect("broker", 1883, 60)
> mqttc.loop_start()
>
> f = open("cap.jpg")
> imagestring = f.read()
> byteArray = bytes(imagestring)
> mqttc.publish("caps", byteArray, 1) # tried 0 and 1, no change
> #mqttc.loop_forever()               # tried loop_forever and the below rc checking loop
> rc = 0
> while rc == 0:
>             rc = mqttc.loop(2)     # tried () and (2), no change
>             print("rc: " + str(rc))
>
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