Re: AW: [equinox-dev] Finding a running instance

[Thomas Hallgren <thomas@xxxxxxx>]

Hi Alexander,
I'm trying to access the wiki but it requires me to log in. I'm probably 
missing something very apparent but no matter how hard I look, I don't 
seem to find any way to register an account.

Are you providing implementations of the ECF remote services? Or is this 
something completely different?

Regards,
Thomas Hallgren


Ziegler, Alexander wrote:
> Hi Thomas,
>
> There is a upcoming open source project Nyota. Nyota focuses a solution for "remote" OSGi Services. A mechanism for service discovery is also planned. We develop Nyota for communication within a distributed RCP application. We call this approach Smart Client - includes also "smart" servers. Nyota is available as EPL 1.0.
>
> I am not sure what your requirement are exactly. For me that sounds liked automatic detecting and discovery like p2p. Is it so?
>
> Currently we are working to release the first public preview of Nyota 0.4.0. Please, look forward to next Thursday to 2007/05/07 (CET) then the open source website for Nyota becomes published. Really it is a first preview :-).
>
> May be Nyota could helpful for your requirements or could be a basis. Everybody can try out. Feedback to Nyota team are wellcome. 
>
> http://eclipse.compeople.eu/wiki/index.php/Nyota:Main
>
>
> Alexander
>
>
>
>
> -----Ursprüngliche Nachricht-----
> Von: equinox-dev-bounces@xxxxxxxxxxx [mailto:equinox-dev-bounces@xxxxxxxxxxx] Im Auftrag von Thomas Hallgren
> Gesendet: Donnerstag, 28. Juni 2007 21:54
> An: Equinox development mailing list
> Betreff: [equinox-dev] Finding a running instance
>
> Hi,
> we have a use-case where one app based on the Eclipse runtime would like 
> to discover other running applications, also based on the Eclipse 
> runtime, on the same machine. Does the Equinox OSGi layer contain some 
> kind of discovery mechanism that would make this possible? If not, does 
> anyone know of other projects that might have a solution or work in 
> progress to solve this?
>
> Thanks,
> Thomas Hallgren
>
>
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