Re: [aspectj-users] Help with pointcut on constructor for class with fie

["Ramnivas Laddad" <ramnivas@xxxxxxxxxxxxxxx>]

This can be done using the experimental -XhasMember option to 'ajc' and then using hasfield() type pattern. Here is untested pointcut for your case:

execution(* new(..)) && within(hasfield(@B * *))

-Ramnivas

On 3/14/07, Pavel Kusch <sunpavlik@xxxxxxxxx> wrote:

Hello,

Please how can I specify a pointcut that would match any constructor
of any class that has at least one instance varible of certain
annotation?

For example if the annotation is @B then:

class A {
  @B int field;

   A() {}
   A(int a) {}
}
//matches both constructors


class A {
  int field;

   A() {}
   A(int a) {}
}
//no match

class A {
  @B int field1;
  @B int field2;

   A() {}
   A(int a) {}
}
//matches both constructors

Thank you,
Pavel Kusch
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